121x^2-198x+81=0

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Solution for 121x^2-198x+81=0 equation: 



121x^2-198x+81=0

a = 121; b = -198; c = +81;
Δ = b2-4ac
Δ = -1982-4·121·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{198}{242}=9/11$

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